EvoN1020v Posted September 25, 2016 Posted September 25, 2016 Hello just re-did my old quiz from 2014 and for b) I got [math]F_{B} = 4,500 N, B_{y} = 13,078.9 N, A_{y} = 1,636.1 N[/math]. Did you get these answers as well? Thanks!
J.C.MacSwell Posted September 25, 2016 Posted September 25, 2016 Hello just re-did my old quiz from 2014 and for b) I got [math]F_{B} = 4,500 N, B_{y} = 13,078.9 N, A_{y} = 1,636.1 N[/math]. Did you get these answers as well? Thanks! Yes. No. No
EvoN1020v Posted September 26, 2016 Author Posted September 26, 2016 Yes. No. No I attempted my calculations again. Still got the same answer for [math]B_y, A_y[/math]. What'd you get?
imatfaal Posted September 26, 2016 Posted September 26, 2016 I attempted my calculations again. Still got the same answer for [math]B_y, A_y[/math]. What'd you get? how many wheels does this car have?
EvoN1020v Posted September 26, 2016 Author Posted September 26, 2016 how many wheels does this car have? Frictionless front wheels and 2 back wheels with [math]F_b[/math] applied at each.
imatfaal Posted September 26, 2016 Posted September 26, 2016 Frictionless front wheels and 2 back wheels with [math]F_b[/math] applied at each. I thought that would be enough of a hint. A quote from the question "and the normal reaction at EACH of the TWO wheels at A and B respectively" I make that four wheels. Your answer spreads a normal force equalling the force of gravity in the opposite direction over two wheels - one at the front and one at the back
EvoN1020v Posted September 26, 2016 Author Posted September 26, 2016 I thought that would be enough of a hint. A quote from the question "and the normal reaction at EACH of the TWO wheels at A and B respectively" I make that four wheels. Your answer spreads a normal force equalling the force of gravity in the opposite direction over two wheels - one at the front and one at the back Yeah that was where I got struck on - the wording of the question. I did my calculations and I hope this is right: [math]F_B=4,500N, B_y=5,576.8N, and A_y=1,780.7N[/math]. If you want the TOTAL reactions at each A and B then just multiply Ay and By by two. 1
J.C.MacSwell Posted September 26, 2016 Posted September 26, 2016 Yeah that was where I got struck on - the wording of the question. I did my calculations and I hope this is right: [math]F_B=4,500N, B_y=5,576.8N, and A_y=1,780.7N[/math]. If you want the TOTAL reactions at each A and B then just multiply Ay and By by two. Looks Good
EvoN1020v Posted September 26, 2016 Author Posted September 26, 2016 Looks Good A second opinion please then I'll be happy with my answers.
imatfaal Posted September 27, 2016 Posted September 27, 2016 Yeah that was where I got struck on - the wording of the question. I did my calculations and I hope this is right: [math]F_B=4,500N, B_y=5,576.8N, and A_y=1,780.7N[/math]. If you want the TOTAL reactions at each A and B then just multiply Ay and By by two. I don't like it; from a quick glom it looks as if you have torque around the CoM - which is wrong.
J.C.MacSwell Posted September 27, 2016 Posted September 27, 2016 I don't like it; from a quick glom it looks as if you have torque around the CoM - which is wrong. I think it balances with the answers given. Did you include the moment from the thrust?
imatfaal Posted September 27, 2016 Posted September 27, 2016 I think it balances with the answers given. Did you include the moment from the thrust? Yeah - but I made the same mistake EvoN made - after pointing he was using only one set of wheels I used only one wheels worth of thrust
EvoN1020v Posted September 27, 2016 Author Posted September 27, 2016 Yeah - but I made the same mistake EvoN made - after pointing he was using only one set of wheels I used only one wheels worth of thrust Here's a screenshot of calculations that I did yesterday. I put down 2 Fb for friction force at both back wheels and 2 normal reactions at each A and B. Is it good?
J.C.MacSwell Posted September 28, 2016 Posted September 28, 2016 Here's a screenshot of calculations that I did yesterday. I put down 2 Fb for friction force at both back wheels and 2 normal reactions at each A and B. Is it good? If it was a test or assignment it would depend on who is marking it. Just my opinion, but it is better to circle the answers to the questions than double them, even if it somewhat makes sense to do so by adding "at A" and "at B". It would be even more important if a mistake was made and you did not get the right answers.
EvoN1020v Posted September 28, 2016 Author Posted September 28, 2016 If it was a test or assignment it would depend on who is marking it. Just my opinion, but it is better to circle the answers to the questions than double them, even if it somewhat makes sense to do so by adding "at A" and "at B". It would be even more important if a mistake was made and you did not get the right answers. Yeah either way I'm confident with my calculations. I only care about the "process" not the answer. Thanks guys!
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