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How much electricity would it take to create the magnetic field to contain the heat required to contain a fusion reaction for generating electricity? and I am not talking about cold fusion

Posted (edited)

There is no single "fusion reaction".

There is possible thousands different combinations.

So there is no single answer to your question.

 

The most common fusion reactions are:

 

1) fusion of proton-proton

[math]p^+ + p^+ \rightarrow D^+ + e^+ + v_e + 0.42 MeV[/math]

[math]e^- + e^+ \rightarrow \gamma + \gamma + 1.022 MeV[/math]

(everywhere available Hydrogen)

 

2) fusion of proton-deuterium

[math]p^+ + D^+ \rightarrow ^3_2He + \gamma + 5.49 MeV[/math]

(hard to get fuel)

 

3) fusion of tritium-deuterium

[math]T^+ + D^+ \rightarrow ^4_2He + n^0 + 17.6 MeV[/math]

(extremely hard to get fuel Tritium produced by f.e. nuclear plants or splitting of Lithium-6 and Lithium-7)

 

Magnetic field is typically created by superconductors,superconducting electromagnets.

 

Creation of electromagnet/magnet, is not enough. There is also needed electricity to ionize fuel inside.

 

According to

https://en.wikipedia.org/wiki/Superconducting_magnet

ITER fusion reactor use 46 kA and produce a field of 13.5 teslas.

Edited by Sensei

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